The potential difference between two square parallel plates is $4.00 \mathrm {~V}$. If the plate separation is $6.00 \mathrm {~cm}$ and they each measure $1.5 \mathrm {~m}$ by $1.5 \mathrm {~m}$, what is the magnitude of the electric field between the plates?

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The Answer of The potential difference between two square parallel plates is $4.00 \mathrm {~V}$. If the plate separation is $6.00 \mathrm {~cm}$ and they each measure $1.5 \mathrm {~m}$ by $1.5 \mathrm {~m}$, what is the magnitude of the electric field between the plates?

The Potential Difference Between Two Square Parallel Plates Is 4.00 V4.00 \mathrm {~V}4.00 V

The Potential Difference Between Two Square Parallel Plates Is $4.00 \mathrm {~V}$