A uniform electric field has the strength of $7.0 \mathrm {~N} / \mathrm { C }$. What is the electric energy density of this field? $\left( \varepsilon _ { 0 } = 8.85 \times 10 ^ { - 12 } \mathrm { C } ^ { 2 } / \mathrm { N } \cdot \mathrm { m } ^ { 2 } \right)$

Question

Quizplus · Accepted Answer

The electric energy density $u$ in a uniform electric field $E$ is given by $u = \frac{1}{2} \varepsilon_0 E^2$. Substituting the given values, $u = \frac{1}{2} \times 8.85 \times 10^{-12} \times (7.0)^2 = 2.2 \times 10^{-10} \mathrm{~J} / \mathrm{m}^3$.

A Uniform Electric Field Has the Strength Of 7.0 N/C7.0 \mathrm {~N} / \mathrm { C }7.0 N/C

A Uniform Electric Field Has the Strength Of $7.0 \mathrm {~N} / \mathrm { C }$