If a charge generator builds a negative static charge of $- 7.00 \mu \mathrm { C }$, how many electrons are transferred to it during this process. $\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)$

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Quizplus · Accepted Answer

The number of electrons transferred can be calculated using the formula: $ \text{Number of electrons} = \frac{\text{Total charge}}{\text{Charge of one electron}} $. Plugging in the values gives $ \frac{7.00 \times 10^{-6} \, \mathrm{C}}{1.60 \times 10^{-19} \, \mathrm{C/electron}} = 4.375 \times 10^{13} $ electrons, which rounds to $4.38 \times 10^{13}$.

If a Charge Generator Builds a Negative Static Charge Of -