Suppose You Wanted to Hold Up an Electron Against the Force

Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above it. How far above the electron would the proton have to be? $( k = 1 / 4 \pi$ $\left. \varepsilon _ { 0 } = 9.0 \times 10 ^ { 9 } \mathrm {~N} \cdot \mathrm { m } ^ { 2 } / \mathrm { C } ^ { 2 } , e = 1.6 \times 10 ^ { - 19 } \mathrm { C } , m _ { \text {proton } } = 1.67 \times 10 ^ { - 27 } \mathrm {~kg} , m _ { \text {electron } } = 9.11 \times 10 ^ { - 31 } \mathrm {~kg} \right)$

A) $3.7 \mathrm {~m}$
B) $5.1 \mathrm {~m}$
C) $1.5 \mathrm {~m}$
D) $4.6 \mathrm {~m}$
E) $2.3 \mathrm {~m}$