A small object with a $5.0 - \mu \mathrm { C }$ charge is accelerating horizontally on a friction-free surface at $0.0050$ $\mathrm { m } / \mathrm { s } 2$ due only to an electric field. If the object has a mass of $2.0 \mathrm {~g}$, what is the magnitude of the electric field?

Question

Quizplus · Accepted Answer

The force on the object is $ F = ma = (0.002 \, \text{kg})(0.0050 \, \text{m/s}^2) = 0.00001 \, \text{N} $. The electric field $ E $ is given by $ E = F/q = 0.00001 \, \text{N} / 5.0 \times 10^{-6} \, \text{C} = 2.0 \, \text{N/C} $.

A Small Object with A 5.0−μC5.0 - \mu \mathrm { C }5.0−μC

A Small Object with A $5.0 - \mu \mathrm { C }$