Object 1 has three times the specific heat capacity and four times the mass of Object 2. The two objects are given the same amount of heat. If the temperature of Object 1 changes by an amount $\Delta T$ the change in temperature of Object 2 will be

Question

Quizplus · Accepted Answer

The amount of heat ($Q$) absorbed or released by an object is given by the formula $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature. For Object 1, $Q = 4m \times 3c \times \Delta T$. For Object 2, $Q = m \times c \times \Delta T_2$. Setting the heat absorbed by both objects equal and solving for $\Delta T_2$ in terms of $\Delta T$, we find that $\Delta T_2 = 12 \Delta T$, indicating that the temperature change of Object 2 is 12 times that of Object 1.

Object 1 Has Three Times the Specific Heat Capacity and Four