A machine part consists of 0.10 kg of iron (of specific heat 470 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K }$ ) and 0.16 kg of copper (of specific heat 390 $\mathrm { J } / \mathrm { Kg } \cdot \mathrm { K } )$ How much heat must be added to the gear to raise its temperature from $18 ^ { \circ } \mathrm { C } \text { to } 53 ^ { \circ } \mathrm { C } ?$

Question

A machine part consists of  0.10 kg of iron (of specific heat 470 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K }$ ) and  0.16 kg of copper (of specific heat 390 $\mathrm { J } / \mathrm { Kg } \cdot \mathrm { K } )$ How much heat must be added to the gear to raise its temperature from $18 ^ { \circ } \mathrm { C } \text { to } 53 ^ { \circ } \mathrm { C } ?$

Quizplus · Accepted Answer

The heat required is calculated using $ Q = mc\Delta T $ for each material and summing them: $ Q_{\text{iron}} = 0.10 \times 470 \times (53-18) $ and $ Q_{\text{copper}} = 0.16 \times 390 \times (53-18) $. Adding these gives approximately 3800 J.

A Machine Part Consists of 0 J/kg⋅K\mathrm { J } / \mathrm { kg } \cdot \mathrm { K }J/kg⋅K

A Machine Part Consists of 0 $\mathrm { J } / \mathrm { kg } \cdot \mathrm { K }$