What is the average translational kinetic energy of an ideal gas at 819 K? The Boltzmann constant is $1.38 \times 10 ^ { - 23 } \mathrm {~J} / \mathrm { K }$
A) $3.77 \times 10 ^ { - 19 } \mathrm {~J}$
B) $1.13 \times 10 ^ { - 17 } \mathrm {~J}$
C) $1.70 \times 10 ^ { - 20 } \mathrm {~J}$
D) $5.65 \times 10 ^ { - 21 } \mathrm {~J}$

Question

What is the average translational kinetic energy of an ideal gas at  819 K? The Boltzmann constant is $1.38 \times 10 ^ { - 23 } \mathrm {~J} / \mathrm { K }$
A) $3.77 \times 10 ^ { - 19 } \mathrm {~J}$
B) $1.13 \times 10 ^ { - 17 } \mathrm {~J}$
C) $1.70 \times 10 ^ { - 20 } \mathrm {~J}$
D) $5.65 \times 10 ^ { - 21 } \mathrm {~J}$

Quizplus · Accepted Answer

The average translational kinetic energy of an ideal gas is given by $\frac{3}{2}kT$. Substituting $k = 1.38 \times 10^{-23} \mathrm{~J/K}$ and $T = 819 \mathrm{~K}$, we get $\frac{3}{2} \times 1.38 \times 10^{-23} \times 819 = 1.70 \times 10^{-20} \mathrm{~J}$.

What Is the Average Translational Kinetic Energy of an Ideal 1.38×10−23 J/K1.38 \times 10 ^ { - 23 } \mathrm {~J} / \mathrm { K }1.38×10−23 J/K

What Is the Average Translational Kinetic Energy of an Ideal $1.38 \times 10 ^ { - 23 } \mathrm {~J} / \mathrm { K }$