Under standard conditions, the density of air is $1.29 \mathrm {~kg} / \mathrm { m } ^ { 3 }$ What is the mass of the air inside a room measuring $4.0 \mathrm {~m} \times 3.0 \mathrm {~m} \times 2.0 \mathrm {~m} ?$
A) 31 kg
B) 19 kg
C) 3.1 kg
D) 1.9 kg
E) 0.32 kg

Question

Under standard conditions, the density of air is $1.29 \mathrm {~kg} / \mathrm { m } ^ { 3 }$ What is the mass of the air inside a room measuring $4.0 \mathrm {~m} \times 3.0 \mathrm {~m} \times 2.0 \mathrm {~m} ?$
A)  31 kg
B)  19 kg
C)  3.1 kg
D)  1.9 kg
E)  0.32 kg

Quizplus · Accepted Answer

The mass of the air can be calculated using the formula $ \text{mass} = \text{density} \times \text{volume} $. The volume of the room is $4.0 \, \text{m} \times 3.0 \, \text{m} \times 2.0 \, \text{m} = 24.0 \, \text{m}^3$. Given the density of air is $1.29 \, \text{kg/m}^3$, the mass of the air in the room is $1.29 \, \text{kg/m}^3 \times 24.0 \, \text{m}^3 = 30.96 \, \text{kg}$, which rounds to approximately 31 kg.

Under Standard Conditions, the Density of Air Is 1.29 kg/m31.29 \mathrm {~kg} / \mathrm { m } ^ { 3 }1.29 kg/m3

Under Standard Conditions, the Density of Air Is $1.29 \mathrm {~kg} / \mathrm { m } ^ { 3 }$