Find the appropriate p-value to test the null hypothesis, H 0 : p 1 = p 2 , using a significance level of 0.05.
-$$\begin{array} { l l }
n _ { 1 } = 100 & \mathrm { n } _ { 2 } = 100 \
\mathrm { x } _ { 1 } = 38 & \mathrm { x } _ { 2 } = 40
\end{array}$$
A).2130
B).0412
C).7718
D).1610

Question

Find the appropriate p-value to test the null hypothesis, H 0 : p 1 = p 2 , using a significance level of 0.05.
-$$\begin{array} { l l } 
n _ { 1 } = 100 & \mathrm { n } _ { 2 } = 100 \
\mathrm { x } _ { 1 } = 38 & \mathrm { x } _ { 2 } = 40
\end{array}$$
A).2130
B).0412
C).7718
D).1610

Quizplus · Accepted Answer

The p-value is calculated using a hypothesis test for the difference between two proportions. Given $n_1 = 100$, $x_1 = 38$, $n_2 = 100$, and $x_2 = 40$, the proportions are $p_1 = \frac{x_1}{n_1} = \frac{38}{100} = 0.38$ and $p_2 = \frac{x_2}{n_2} = \frac{40}{100} = 0.40$. The p-value of approximately 0.7718 suggests that there is not enough evidence to reject the null hypothesis at the 0.05 significance level, indicating that the difference between the two proportions is not statistically significant.

Find the Appropriate P-Value to Test the Null Hypothesis, H0 n1=100n2=100x1=38x2=40\begin{array} { l l } n _ { 1 } = 100 & \mathrm { n } _ { 2 } = 100 \\\mathrm { x } _ { 1 } = 38 & \mathrm { x } _ { 2 } = 40\end{array}n1​=100x1​=38​n2​=100x2​=40​

Find the Appropriate P-Value to Test the Null Hypothesis, H₀ $\begin{array} { l l } n _ { 1 } = 100 & \mathrm { n } _ { 2 } = 100 \\\mathrm { x } _ { 1 } = 38 & \mathrm { x } _ { 2 } = 40\end{array}$