Find the margin of error
-$90 \% ; n = 9 ; \sigma = 4.2 ;$ population appears to be very skewed.
A) $\mathrm { z } _ { \alpha / 2 } = 2.896$
B) $\mathrm { z } _ { \alpha / 2 } = 2.306$
C) $\mathrm { z } _ { \alpha / 2 } = 2.365$
D) Neither the normal nor the $t$ distribution applies.

Question

Quizplus · Accepted Answer

Given the small sample size (n = 9) and the very skewed population, neither the normal distribution (which requires a larger sample size or a normally distributed population) nor the t-distribution (which is more forgiving with smaller sample sizes but still assumes the population is approximately normally distributed) can be accurately used to determine the margin of error.

Find the Margin of Error - 90%;n=9;σ=4.2;90 \% ; n = 9 ; \sigma = 4.2 ;90%;n=9;σ=4.2;

Find the Margin of Error
- $90 \% ; n = 9 ; \sigma = 4.2 ;$