Use the given values of n and p to find the minimum usual value µ - 2? and the maximum usual value µ + 2?
-n = 252, p = 0.261
A)Minimum: 79.716; maximum: 51.828
B)Minimum: 58.8; maximum: 72.744
C)Minimum: 55.912; maximum: 75.632
D)Minimum: 51.828; maximum: 79.716

Question

Quizplus · Accepted Answer

The mean (µ) of a binomial distribution is found using µ = np, and the standard deviation (σ) is found using the formula σ = sqrt(np(1-p)). For n = 252 and p = 0.261, µ = 252 * 0.261 = 65.772 and σ = sqrt(252 * 0.261 * (1 - 0.261)) = 6.972. The minimum usual value is µ - 2σ = 65.772 - 2(6.972) = 51.828, and the maximum usual value is µ + 2σ = 65.772 + 2(6.972) = 79.716.

Use the Given Values of N and P to Find