Assume that a probability distribution is described by the discrete random variable x that can assume the values 1, 2, . . . , n; and those values are equally likely. This probability has mean and standard deviation described as follows: $$\mu = \frac { \mathrm { n } + 1 } { 2 } \text { and } \sigma = \sqrt { \frac { \mathrm { n } ^ { 2 } - 1 } { 12 } }$$ Show that the formulas hold for the case of n = 7.

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The Answer of Assume that a probability distribution is described by the discrete random variable x that can assume the values 1, 2, . . . , n; and those values are equally likely. This probability has mean and standard deviation described as follows: $$\mu = \frac { \mathrm { n } + 1 } { 2 } \text { and } \sigma = \sqrt { \frac { \mathrm { n } ^ { 2 } - 1 } { 12 } }$$ Show that the formulas hold for the case of n = 7.

Assume That a Probability Distribution Is Described by the Discrete μ=n+12 and σ=n2−112\mu = \frac { \mathrm { n } + 1 } { 2 } \text { and } \sigma = \sqrt { \frac { \mathrm { n } ^ { 2 } - 1 } { 12 } }μ=2n+1​ and σ=12n2−1​​

Assume That a Probability Distribution Is Described by the Discrete $\mu = \frac { \mathrm { n } + 1 } { 2 } \text { and } \sigma = \sqrt { \frac { \mathrm { n } ^ { 2 } - 1 } { 12 } }$