Solve the problem.
-The library is to be given 3 books as a gift. The books will be selected from a list of 18 titles. If each book selected must have a different title, how many possible selections are there?
A)4896
B)1.067062284e+15
C)816
D)6.402373706e+15

Question

Quizplus · Accepted Answer

The number of ways to select 3 books from 18, with no repetition, is calculated using the combination formula: $C(n, k) = \frac{n!}{k!(n-k)!}$, where $n$ is the total number of items (18 books), and $k$ is the number of items to choose (3 books). Thus, $C(18, 3) = \frac{18!}{3!(18-3)!} = \frac{18 \times 17 \times 16}{3 \times 2 \times 1} = 816$.

Solve the Problem. -The Library Is to Be Given 3 Books as a Books