Solve the problem.
-A tourist in France wants to visit 10 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order?
A) $3,628,800$
B) $\frac { 1 } { 3,628,800 }$
C) $\frac { 1 } { 100 }$
D) $\frac { 1 } { 10 }$

Question

Solve the problem.
-A tourist in France wants to visit 10 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order? 
A) $3,628,800$
B) $\frac { 1 } { 3,628,800 }$
C) $\frac { 1 } { 100 }$
D) $\frac { 1 } { 10 }$

Quizplus · Accepted Answer

The total number of ways to arrange the visit to 10 cities is 10!, which is 3,628,800. There is only one way to visit the cities in alphabetical order, so the probability is $\frac{1}{3,628,800}$.

Solve the Problem 3,628,8003,628,8003,628,800 B) 13,628,800\frac { 1 } { 3,628,800 }3,628,8001​

Solve the Problem $3,628,800$ B) $\frac { 1 } { 3,628,800 }$