Find the midrange for the given sample data.
-Compute the variance. A class of sixth grade students kept accurate records on the amount of time they spent playing video games during a one-week period. The times (in hours)are listed below:
$\begin{array} { l l l l l } 19.8 & 21.6 & 13.4 & 26.7 & 25.6 \end{array}$
$\begin{array} { l l l l l } 19.2 & 17.0 & 12.9 & 26.8 & 15.2 \end{array}$
A)152.13
B)25.14
C)27.84
D)27.94

Question

Find the midrange for the given sample data.
-Compute the variance. A class of sixth grade students kept accurate records on the amount of time they spent playing video games during a one-week period. The times (in hours)are listed below:
 $\begin{array} { l l l l l } 19.8 & 21.6 & 13.4 & 26.7 & 25.6 \end{array}$
$\begin{array} { l l l l l } 19.2 & 17.0 & 12.9 & 26.8 & 15.2 \end{array}$
A)152.13
B)25.14
C)27.84
D)27.94

Quizplus · Accepted Answer

The midrange is the average of the highest and lowest values in a data set. In this case, the highest value is 26.8 and the lowest value is 12.9, so the midrange is (26.8 + 12.9) / 2 = 19.85.The variance is a measure of how spread out the data is. It is calculated by finding the average of the squared differences between each data point and the mean. In this case, the mean is (19.8 + 21.6 + 13.4 + 26.7 + 25.6 + 19.2 + 17.0 + 12.9 + 26.8 + 15.2) / 10 = 19.85. The variance is then calculated as [(19.8 - 19.85)^2 + (21.6 - 19.85)^2 + (13.4 - 19.85)^2 + (26.7 - 19.85)^2 + (25.6 - 19.85)^2 + (19.2 - 19.85)^2 + (17.0 - 19.85)^2 + (12.9 - 19.85)^2 + (26.8 - 19.85)^2 + (15.2 - 19.85)^2] / 9 = 27.94.

Find the Midrange for the Given Sample Data 19.821.613.426.725.6\begin{array} { l l l l l } 19.8 & 21.6 & 13.4 & 26.7 & 25.6 \end{array}19.8​21.6​13.4​26.7​25.6​

Find the Midrange for the Given Sample Data $\begin{array} { l l l l l } 19.8 & 21.6 & 13.4 & 26.7 & 25.6 \end{array}$