Find the range, variance, and standard deviation for each of the two samples, then compare the two sets of results.
-A company had 80 employees whose salaries are summarized in the frequency distribution below. Find the standard deviation. $$\begin{array} { r | c }
\text { Salary } & \text { Employees } \
\hline 5,001 - 10,000 & 11 \
10,001 - 15,000 & 15 \
15,001 - 20,000 & 19 \
20,001 - 25,000 & 10 \
25,001 - 30,000 & 25
\end{array}$$
A)s = 7168.6
B)s = 7742.1
C)s = 7527.0
D)s = 7957.1

Question

Find the range, variance, and standard deviation for each of the two samples, then compare the two sets of results.
-A company had 80 employees whose salaries are summarized in the frequency distribution below. Find the standard deviation. $$\begin{array} { r | c } 
\text { Salary } & \text { Employees } \
\hline 5,001 - 10,000 & 11 \
10,001 - 15,000 & 15 \
15,001 - 20,000 & 19 \
20,001 - 25,000 & 10 \
25,001 - 30,000 & 25
\end{array}$$
A)s = 7168.6
B)s = 7742.1
C)s = 7527.0
D)s = 7957.1

Quizplus · Accepted Answer

The standard deviation is the square root of the variance. The variance is the average of the squared differences from the mean. The mean is the average of the data. The range is the difference between the highest and lowest values.The mean is (5000.5 + 12500.5 + 17500.5 + 22500.5 + 27500.5) / 5 = 17502.5.The variance is [(5000.5 - 17502.5)^2 + (12500.5 - 17502.5)^2 + (17500.5 - 17502.5)^2 + (22500.5 - 17502.5)^2 + (27500.5 - 17502.5)^2] / 5 = 51714290.5.The standard deviation is sqrt(51714290.5) = 7192.1.Therefore, the standard deviation is 7192.1.

Find the Range, Variance, and Standard Deviation for Each of the Two