Find the standard deviation of the data summarized in the given frequency distribution.
-A body temperature of 96.8° F given that human body temperatures have a mean of 98.20° F and a standard deviation of 0.62°.
A)-2.3; not unusual
B)2.3; unusual
C)-2.3; unusual
D)-1.4; not ususal

Question

Quizplus · Accepted Answer

To find how unusual a body temperature of 96.8°F is, we calculate its z-score using the formula $z = \frac{(X - \mu)}{\sigma}$, where $X$ is the value in question, $\mu$ is the mean, and $\sigma$ is the standard deviation. Plugging in the given values: $z = \frac{(96.8 - 98.20)}{0.62} = \frac{-1.4}{0.62} \approx -2.26$, which rounds to -2.3. A z-score of -2.3 is considered unusual because it is more than 2 standard deviations away from the mean.

Find the Standard Deviation of the Data Summarized in the Given