Provide an appropriate response.
-Fill in the missing entries in the following partially completed one-way ANOVA table. $\begin{array}{|l|c|c|c|c|}
\hline \text { Source } & \text { df } & \text { SS } & \text { MS=SS/df } & \text { F-statistic } \
\hline \text { Treatment } & & 25.2 & & \
\hline \text { Error } & 24 & & 3.5 & \
\hline \text { Total } & 28 & & & \
\hline
\end{array}$
A)
$\begin{array}{|l|c|c|c|c|}
\hline \text { Source } & \text { df } & \text { SS } & \text { MS=SS/df } & \text { F-statistic } \
\hline \text { Treatment } & 4 & 25.2 & 6.30 & 1.80 \
\hline \text { Error } & 24 & 84.0 & 3.5 & \
\hline \text { Total } & 28 & 25.35 & & \
\hline
\end{array}$
B)
$\begin{array}{|l|c|c|c|c|}
\hline \text { Source } & \text { df } & \text { SS } & \text { MS=SS/df } & \text { F-statistic } \
\hline \text { Treatment } & 4 & 25.2 & 6.30 & 0.56 \
\hline \text { Error } & 24 & 84.0 & 3.5 & \
\hline \text { Total } & 28 & 109.2 & & \
\hline
\end{array}$
C)
$\begin{array}{|l|c|c|c|c|}
\hline \text { Source } & \text { df } & \text { SS } & \text { MS=SS/df } & \text { F-statistic } \
\hline \text { Treatment } & 4 & 25.2 & 6.30 & 1.80 \
\hline \text { Error } & 24 & 84.0 & 3.5 & \
\hline \text { Total } & 28 & 109.2 & & \
\hline
\end{array}$
D)
$\begin{array}{|l|c|c|c|c|}
\hline \text { Source } & \text { df } & \text { SS } & \text { MS=SS/df } & \text { F-statistic } \
\hline \text { Treatment } & 52 & 25.2 & 0.48 & 374.40 \
\hline \text { Error } & 24 & 84.0 & 3.5 & \
\hline \text { Total } & 28 & 109.2 & & \
\hline
\end{array}$

Question

Quizplus · Accepted Answer

The degrees of freedom for Treatment is calculated as $Total\ df - Error\ df = 28 - 24 = 4$. The SS for Error is calculated by multiplying the MS by the df, $24 \times 3.5 = 84.0$. The Total SS is the sum of Treatment SS and Error SS, $25.2 + 84.0 = 109.2$. The MS for Treatment is $SS/df = 25.2/4 = 6.3$. The F-statistic is calculated as $MS_{Treatment} / MS_{Error} = 6.3 / 3.5 = 1.8$.

Provide an Appropriate Response A) B) C) D)