Rewrite the following as a product of trigonometric functions.
-Find $\cot \theta$ if $\sec \theta = - \frac { \sqrt { 29 } } { 5 }$ and $\theta$ is in quadrant II.
A) $- \frac { \sqrt { 29 } } { 2 }$
B) $\frac { \sqrt { 29 } } { 2 }$
C) $- \frac { 5 } { 2 }$
D) $\frac { 2 } { 5 }$

Question

Quizplus · Accepted Answer

In quadrant II, cosine is negative, so $\cos \theta = -\frac{5}{\sqrt{29}}$. Using $\sin^2 \theta + \cos^2 \theta = 1$, we find $\sin \theta = \frac{2\sqrt{6}}{\sqrt{29}}$. Thus, $\cot \theta = \frac{\cos \theta}{\sin \theta} = -\frac{5}{2}$.

Rewrite the Following as a Product of Trigonometric Functions cot⁡θ\cot \thetacotθ

Rewrite the Following as a Product of Trigonometric Functions $\cot \theta$