Express the function as a trigonometric function of x.
-$$1 + \tan ^ { 2 } x = \frac { \cos ^ { 2 } x } { 1 - \cos ^ { 2 } x }$$
A) Identity
B) Not an Identity

Name: Express the function as a trigonometric function of x. -\[1 + \tan ^ { 2 } x = \frac { \cos ^ { 2 } x } { 1 - \cos ^ { 2 } x }\] A) Identity B) Not an Identity
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Question

Quizplus · Accepted Answer

The given equation is incorrect when expressed as a trigonometric function of x. The correct identity related to $\tan^2x$ is $1 + \tan^2x = \sec^2x$, not the given expression.

Express the Function as a Trigonometric Function of X 1+tan⁡2x=cos⁡2x1−cos⁡2x1 + \tan ^ { 2 } x = \frac { \cos ^ { 2 } x } { 1 - \cos ^ { 2 } x }1+tan2x=1−cos2xcos2x​

Express the Function as a Trigonometric Function of X $1 + \tan ^ { 2 } x = \frac { \cos ^ { 2 } x } { 1 - \cos ^ { 2 } x }$