Solve the problem.
-The index of refraction for air, Ia, is 1.0003. The index of refraction for water, Iw, is 1.3. If $\frac { \mathrm { I } _ { \mathrm { W } } } { \mathrm { I } _ { \mathrm { a } } } = \frac { \sin \mathrm { A } } { \sin \mathrm { W } }$, and $\mathrm { A } = 31.5 ^ { \circ }$, find $\mathrm { W }$ to the nearest tenth.

A) $22.7 ^ { \circ }$
B) $23.7 ^ { \circ }$
C) $21.7 ^ { \circ }$
D) $20.7 ^ { \circ }$

Question

Solve the problem.
-The index of refraction for air, Ia, is 1.0003. The index of refraction for water, Iw, is 1.3. If $\frac { \mathrm { I } _ { \mathrm { W } } } { \mathrm { I } _ { \mathrm { a } } } = \frac { \sin \mathrm { A } } { \sin \mathrm { W } }$, and $\mathrm { A } = 31.5 ^ { \circ }$, find $\mathrm { W }$ to the nearest tenth.

A) $22.7 ^ { \circ }$ 
B) $23.7 ^ { \circ }$ 
C) $21.7 ^ { \circ }$ 
D) $20.7 ^ { \circ }$

Quizplus · Accepted Answer

The Answer of Solve the problem.
-The index of refraction for air, Ia, is 1.0003. The index of refraction for water, Iw, is 1.3. If $\frac { \mathrm { I } _ { \mathrm { W } } } { \mathrm { I } _ { \mathrm { a } } } = \frac { \sin \mathrm { A } } { \sin \mathrm { W } }$, and $\mathrm { A } = 31.5 ^ { \circ }$, find $\mathrm { W }$ to the nearest tenth.

A) $22.7 ^ { \circ }$ 
B) $23.7 ^ { \circ }$ 
C) $21.7 ^ { \circ }$ 
D) $20.7 ^ { \circ }$

Solve the Problem IWIa=sin⁡Asin⁡W\frac { \mathrm { I } _ { \mathrm { W } } } { \mathrm { I } _ { \mathrm { a } } } = \frac { \sin \mathrm { A } } { \sin \mathrm { W } }Ia​IW​​=sinWsinA​

Solve the Problem $\frac { \mathrm { I } _ { \mathrm { W } } } { \mathrm { I } _ { \mathrm { a } } } = \frac { \sin \mathrm { A } } { \sin \mathrm { W } }$