Solve the Problem $\frac { \mathrm { c } _ { 1 } } { \mathrm { c } _ { 2 } } = \frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } }$

Solve the problem.
-Snell's Law states that $\frac { \mathrm { c } _ { 1 } } { \mathrm { c } _ { 2 } } = \frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } }$ . Use this law to find the requested value. If $\mathrm { c } _ { 1 } = 8 \times 10 ^ { 8 }$ , $c _ { 2 } = 6.14 \times 10 ^ { 8 } , \theta _ { 2 } = 36 ^ { \circ }$ , find $\theta _ { 1 }$ . Round your answer to the nearest degree.

A) $\theta _ { 1 } = 48 ^ { \circ }$
B) $\theta _ { 1 } = 51 ^ { \circ }$
C) $\theta _ { 1 } = 53 ^ { \circ }$
D) $\theta _ { 1 } = 50 ^ { \circ }$