Solve the problem.
-Snell's Law states that $\frac { c _ { 1 } } { c _ { 2 } } = \frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } }$. Use this law to find the requested value. If $c _ { 1 } = 6 \times 10 ^ { 8 }$, $c _ { 2 } = 4.66 \times 10 ^ { 8 } , \theta _ { 1 } = 43 ^ { \circ }$, find $\theta _ { 2 }$. Round your answer to the nearest degree.
A) $\theta _ { 2 } = 31 ^ { \circ }$
B) $\theta _ { 2 } = 34 ^ { \circ }$
C) $\theta _ { 2 } = 32 ^ { \circ }$
D) $\theta _ { 2 } = 35 ^ { \circ }$

Question

Quizplus · Accepted Answer

Snell's Law states that $\frac { c _ { 1 } } { c _ { 2 } } = \frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } }$. Substitute the given values into the equation and solve for $\theta _ { 2 }$.$\frac { 6 \times 10 ^ { 8 } } { 4.66 \times 10 ^ { 8 } } = \frac { \sin 43 ^ { \circ } } { \sin \theta _ { 2 } }$$\frac { 6 } { 4.66 } = \frac { \sin 43 ^ { \circ } } { \sin \theta _ { 2 } }$$\sin \theta _ { 2 } = \frac { 4.66 } { 6 } \sin 43 ^ { \circ }$$\theta _ { 2 } = \sin ^ { - 1 } \left ( \frac { 4.66 } { 6 } \sin 43 ^ { \circ } \right )$$\theta _ { 2 } \approx 32 ^ { \circ }$

Solve the Problem c1c2=sin⁡θ1sin⁡θ2\frac { c _ { 1 } } { c _ { 2 } } = \frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } }c2​c1​​=sinθ2​sinθ1​​

Solve the Problem $\frac { c _ { 1 } } { c _ { 2 } } = \frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } }$