What is the Q value for the following reaction? ⁷Li +¹p = ⁴He + ⁴He
(7.016005) (1.007825) (4.002603) (4.002603)

Question

What is the Q value for the following reaction? ⁷Li +¹p = ⁴He + ⁴He (7.016005) (1.007825) (4.002603) (4.002603)

Quizplus · Accepted Answer

The Q value is calculated using the mass-energy equivalence principle. The mass defect is the difference between the initial and final masses, converted to energy using E=mc². The initial mass is 7.016005 + 1.007825 = 8.02383 u, and the final mass is 2 * 4.002603 = 8.005206 u. The mass defect is 8.02383 - 8.005206 = 0.018624 u. Converting this to energy (1 u = 931.5 MeV), the Q value is 0.018624 * 931.5 = 17.35 MeV.

What Is the Q Value for the Following Reaction?