The reaction ²H + ²H → ³H + ¹H releases 4.03 MeV of energy. If one kilogram of deuterium were made to go through this reaction, how much energy would be produced?

Question

Quizplus · Accepted Answer

The reaction releases 4.03 MeV of energy per reaction. One kilogram of deuterium contains 6.022 × 10²⁶ atoms. Therefore, the total energy released would be:(4.03 MeV/reaction) × (6.022 × 10²⁶ atoms/kg) × (1.602 × 10^-13 J/MeV) = 9.7 × 10¹³ J

The Reaction 2H + 2H → 3H + 1H Releases

The Reaction ²H + ²H → ³H + ¹H Releases