A diatomic quantum mechanical oscillator has a moment of inertia of 7.73 × 10^-⁴⁵ kg∙m². What is the rotational energy in the quantum state characterized by L = 2? A)2.27 × 10^-⁵ eV B)2.72 × 10^-⁵ eV C)5.87 × 10^-⁵ eV D)7.22 × 10^-⁵ eV E)8.71 × 10^-⁵ eV

Question

Quizplus · Accepted Answer

The rotational energy for a quantum mechanical oscillator is given by E = L(L+1)ħ²/(2I). For L = 2, I = 7.73 × 10⁻⁴⁵ kg∙m², and ħ = 1.0545718 × 10⁻³⁴ J∙s, the energy is calculated and converted to eV, resulting in approximately 2.72 × 10⁻⁵ eV.

A Diatomic Quantum Mechanical Oscillator Has a Moment of Inertia