In a ruby laser, an electron jumps from a higher energy level to a lower one. If the energy difference between the two levels is 1.8 eV, what is the wavelength of the emitted photon?
A)350 nm
B)470 nm
C)650 nm
D)690 nm
E)960 nm

Question

Quizplus · Accepted Answer

The energy of a photon is given by E = hc/λ, where h is Planck's constant and c is the speed of light. Solving for λ gives λ = hc/E. Substituting the given energy difference (1.8 eV) and converting it to joules, we find the wavelength to be approximately 690 nm.

In a Ruby Laser, an Electron Jumps from a Higher