A beam of light with a frequency range of 3.01 × 10¹⁴ Hz - 6.10 × 10¹⁴ Hz is incident on a metal surface. If the work function of the metal surface is 2.20 eV, what is the range of frequencies in this beam of light that will be responsible for ejecting electrons from this metal surface? A) 1.12 × 10¹⁴ Hz - 5.31 × 10¹⁴ Hz B) 1.12 × 10¹⁴ Hz - 3.10 × 10¹⁴ Hz C) 3.01 × 10¹⁴ Hz - 6.10 × 10¹⁴ Hz D) 5.31 × 10¹⁴ Hz - 6.10 × 10¹⁴ Hz E) None

Question

Quizplus · Accepted Answer

The threshold frequency (f₀) can be calculated using the work function (φ) and Planck's constant (h): f₀ = φ/h. For φ = 2.20 eV, f₀ ≈ 5.31 × 10¹⁴ Hz. Frequencies above this will eject electrons.

A Beam of Light with a Frequency Range of 3