What is the de Broglie wavelength of an electron whose kinetic energy is 1.0 eV?
A)520 nm
B)8.2 nm
C)0.64 nm
D)52 nm
E)1.2 nm

Question

Quizplus · Accepted Answer

The de Broglie wavelength λ is given by λ = h/p, where h is Planck's constant and p is the momentum. For an electron with kinetic energy (KE) of 1.0 eV, the momentum p can be calculated using p = sqrt(2mKE), where m is the electron mass. Substituting the values, the de Broglie wavelength is approximately 1.2 nm.

What Is the De Broglie Wavelength of an Electron Whose