If the momentum of an electron is 1.95 × 10^-27 kg∙m/s, what is its de Broglie wavelength? A) 340 nm B) 210 nm C) 170 nm D) 420 nm E) 520 nm

Question

Quizplus · Accepted Answer

The de Broglie wavelength (λ) is given by the formula:
λ = h/p
Where h is the Planck's constant and p is the momentum of the particle.

Substituting the given values, we get:
λ = (6.626 × 10^-34 J∙s)/(1.95 × 10^-27 kg∙m/s) 
λ = 3.40 × 10^-7 m 
λ = 340 nm

Therefore, the correct answer is A) 340 nm.

If the Momentum of an Electron Is 1