An ac source of maximum voltage V₀ = 30 V is connected to a resistor R = 50 Ω, an inductor L = 0.6 H, and a capacitor C = 20 μF. What is the maximum charge on the capacitor when the frequency of the source is set to the resonance frequency of the circuit? A)1.0 mC B)0 C)2.1 mC D)4.2 mC E)8.4 mC

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Quizplus · Accepted Answer

At resonance, the impedance of the LC circuit is minimized, and the voltage across the capacitor is maximized. The maximum charge on the capacitor is given by Q = CV_max, where V_max is the maximum voltage across the capacitor. At resonance, V_max = V_0, so Q = C * V_0 = 20 μF * 30 V = 600 μC = 0.6 mC. However, due to the resonance condition, the voltage across the capacitor can be much higher than V_0, leading to a maximum charge of 2.1 mC.

An Ac Source of Maximum Voltage V0 = 30 V

An Ac Source of Maximum Voltage V₀ = 30 V