A solenoid of 200 turns carrying a current of 2 A has a length of 25 cm. What is the magnitude of the magnetic field at the center of the solenoid?
A) 2 mT
B) 3 mT
C) 4 mT
D) 5 mT
E) 6 mT

Question

Quizplus · Accepted Answer

The magnetic field inside a solenoid is given by B = μ₀ * (N/L) * I, where μ₀ = 4π x 10⁻⁷ Tm/A, N = 200 turns, L = 0.25 m, and I = 2 A. Substituting these values gives B = 2 x 10⁻³ T or 2 mT.

A Solenoid of 200 Turns Carrying a Current of 2