A proton travels through a potential of 1.0 kV and then moves into a magnetic field of 0.040 T. What is the radius of the proton's resulting orbit?

Question

Quizplus · Accepted Answer

The kinetic energy gained by the proton is equal to the electric potential energy, which is qV = 1.6 x 10^-19 C * 1.0 x 10^3 V = 1.6 x 10^-16 J. The velocity of the proton can be found using the kinetic energy formula: KE = 0.5 * m * v^2. Solving for v gives v = sqrt(2 * KE / m). The radius of the orbit in a magnetic field is given by r = mv / (qB). Substituting the values, we find r ≈ 0.11 m.

A Proton Travels Through a Potential of 1