A silver wire has a cross sectional area A = 2mm². A total of of 9.4 × 10¹⁸ electrons pass through the wire in a time t = 3s. Silver has n_q = 5.8 × 10²⁸ electrons/m³. What is the drift velocity of these electrons?

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Quizplus · Accepted Answer

The drift velocity (v_d) can be calculated using the formula: v_d = I / (n_q * A * e), where I is the current, n_q is the electron density, A is the cross-sectional area, and e is the charge of an electron (1.6 × 10^-19 C). First, calculate the current I = (number of electrons * e) / t = (9.4 × 10^18 * 1.6 × 10^-19) / 3 = 5.0133 × 10^-2 A. Then, v_d = 5.0133 × 10^-2 / (5.8 × 10^28 * 2 × 10^-6 * 1.6 × 10^-19) = 2.7 × 10^-5 m/s.

A Silver Wire Has a Cross Sectional Area a =