FIGURE 23-7
-Two identical charges of magnitude 6.0 μC are placed at the corners of the base of an equilateral triangle, as shown in Fig. 23-7. What is the electric potential at the vertex, P, of the triangle due to these charges?

Question

FIGURE 23-7 
-Two identical charges of magnitude 6.0 μC are placed at the corners of the base of an equilateral triangle, as shown in Fig. 23-7. What is the electric potential at the vertex, P, of the triangle due to these charges?

Quizplus · Accepted Answer

The electric potential at a point due to a point charge is given by V = kQ/r. For two identical charges at the base of an equilateral triangle, the potential at the vertex is the sum of the potentials due to each charge. Since the charges are identical and equidistant from the vertex, the potential is 2(kQ/r). Given Q = 6.0 μC and using k = 8.99 x 10^9 Nm²/C², the potential is 54 kV.

FIGURE 23-7 -Two Identical Charges of Magnitude 6.0 μC Are Placed at Are