A person tries to heat up her bath water by adding 5.0 L of water at 80°C to 60 L of water at 30°C. What is the final temperature of the water?

Question

Quizplus · Accepted Answer

The correct answer is A because the final temperature of the water will be 34°C. This can be calculated using the formula:Q = mcΔTwhere Q is the heat transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.In this case, the heat transferred is:Q = (5.0 L)(1 kg/L)(4187 J/kg°C)(80°C - 34°C) = 628,050 JThe mass of the water is:m = (5.0 L + 60 L)(1 kg/L) = 65 kgThe specific heat capacity of water is:c = 4187 J/kg°CThe change in temperature is:ΔT = 34°C - 30°C = 4°CSubstituting these values into the formula, we get:628,050 J = (65 kg)(4187 J/kg°C)(4°C)Solving for ΔT, we get:ΔT = 34°CTherefore, the final temperature of the water will be 34°C.

A Person Tries to Heat Up Her Bath Water by Adding