The amplitude of a 3.00-kg object in simple harmonic motion is 10.0 m. The maximum speed of the object is 5.00 m/s What is the frequency of simple harmonic motion? A)0.500 Hz B)2.78 × 10^-² Hz C)2.00 Hz D)7.96 × 10^-² Hz E)3.14 Hz

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Quizplus · Accepted Answer

The frequency of simple harmonic motion is given by:f = 1/T = 1/(2π√(m/k))where T is the period, m is the mass, and k is the spring constant.We can find the spring constant from the amplitude and maximum speed:k = mω^2 = m(v_max/A)^2where ω is the angular frequency.Substituting this into the equation for the frequency, we get:f = 1/(2π√(m/(m(v_max/A)^2))) = v_max/(2πA)Plugging in the given values, we get:f = 5.00 m/s/(2π(10.0 m)) = 7.96 × 10^-2 Hz

The Amplitude of a 3