The amplitude of a 3.00-kg object in simple harmonic motion is 6.00 m. The maximum acceleration of the object is 5.00 m/s². What is the period of simple harmonic motion? A)6.88 s B)1.20 s C)0.278 s D)0.833 s E)7.54 s

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Quizplus · Accepted Answer

The maximum acceleration in simple harmonic motion is given by $ a_{max} = \omega^2 A $, where $ \omega $ is the angular frequency and $ A $ is the amplitude. Solving for $ \omega $, we have $ \omega = \sqrt{\frac{a_{max}}{A}} = \sqrt{\frac{5.00}{6.00}} $. The period $ T $ is given by $ T = \frac{2\pi}{\omega} $. Calculating this gives approximately 6.88 s.

The Amplitude of a 3