A crank is being turned clockwise at 120 rev/min. The handle is 10 cm from the axle of the crank. An observer some distance away sees the crank edge-on so he only perceives the vertical motion of the crank and not the horizontal motion. What equation describes the motion of the handle seen by the observer if at t=0 the crank is at y = 0 and moving in the negative y direction?
A)y = (10 cm)cos((12.6 rad/s)t +3π/2)
B)y = (10 cm)cos((12.6 rad/s + π)t)
C)y = (10 cm)cos((12.6 rad/s)t - π/2)
D)y = (10 cm)cos((12.6 rad/s)t)
E)y = (10 cm)cos((12.6 rad/s)t + π/2)

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The Answer of A crank is being turned clockwise at 120 rev/min. The handle is 10 cm from the axle of the crank. An observer some distance away sees the crank edge-on so he only perceives the vertical motion of the crank and not the horizontal motion. What equation describes the motion of the handle seen by the observer if at t=0 the crank is at y = 0 and moving in the negative y direction?
A)y = (10 cm)cos((12.6 rad/s)t +3π/2)
B)y = (10 cm)cos((12.6 rad/s + π)t)
C)y = (10 cm)cos((12.6 rad/s)t - π/2)
D)y = (10 cm)cos((12.6 rad/s)t)
E)y = (10 cm)cos((12.6 rad/s)t + π/2)

A Crank Is Being Turned Clockwise at 120 Rev/min