What is the absolute pressure at a distance 5.00 m below the surface of a lake? Assume the density of the water in the lake is 1000 kg/m³. A)5.00 × 10³ N/m² B)1.50 × 10⁵ N/m² C)0.49 × 10⁵ N/m² D)1.05 × 10⁵ N/m² E)4.66 × 10⁵ N/m²

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Quizplus · Accepted Answer

The absolute pressure at a depth h in a fluid is given by:P = P_atm + ρghwhere:P_atm is the atmospheric pressureρ is the density of the fluidg is the acceleration due to gravityh is the depthIn this case, we have:P_atm = 1.01 × 10^5 N/m^2ρ = 1000 kg/m^3g = 9.81 m/s^2h = 5.00 mPlugging these values into the equation, we get:P = 1.01 × 10^5 N/m^2 + (1000 kg/m^3)(9.81 m/s^2)(5.00 m)= 1.50 × 10^5 N/m^2Therefore, the absolute pressure at a distance 5.00 m below the surface of the lake is 1.50 × 10^5 N/m^2.

What Is the Absolute Pressure at a Distance 5