A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg∙m². If the arms are pulled in so the moment of inertia decreases to 1.80 kg∙m², what is the final angular speed? A)2.25 rad/s B)4.60 rad/s C)6.25 rad/s D)1.76 rad/s E)0.81 rad/s

Question

Quizplus · Accepted Answer

The conservation of angular momentum states that the initial angular momentum equals the final angular momentum. Thus, (I_initial)(ω_initial) = (I_final)(ω_final). Solving for ω_final gives (2.25 kg∙m²)(5.00 rad/s) = (1.80 kg∙m²)(ω_final), resulting in ω_final = 6.25 rad/s.

A Figure Skater Rotating at 5