A linear spring has a spring constant of 20 N/m. How far would it have to be stretched to have a potential energy of 0.10 J?

Name: A linear spring has a spring constant of 20 N/m. How far would it have to be stretched to have a potential energy of 0.10 J?
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Question

Quizplus · Accepted Answer

The potential energy stored in a spring is given by the formula PE = 0.5 * k * x^2, where k is the spring constant and x is the displacement. Solving for x, we get x = sqrt((2 * PE) / k) = sqrt((2 * 0.10 J) / 20 N/m) = 0.10 m.

A Linear Spring Has a Spring Constant of 20 N/m