An object of mass 4 kg starts at rest from the top of a rough inclined plane of height 10 m as shown in Fig. 8-9. If the speed of the object at the bottom of the inclined plane is 10 m/s, how much work is done by the force of friction? Use g = 10 m/s².

Question

Quizplus · Accepted Answer

Work done by friction = Change in kinetic energy + Change in potential energy= (1/2)mv^2 - mgh= (1/2)(4 kg)(10 m/s)^2 - (4 kg)(10 m/s^2)(10 m)= -200 J

An Object of Mass 4 Kg Starts at Rest from the Top