A race car enters a flat 200-m radius curve at a speed of 20.0 m/s while increasing its speed at a constant 2.00 m/s². If the coefficient of static friction is 0.700, what will the speed of the car be when the car begins to slide? A)36.2 m/s B)24.3 m/s C)37.1 m/s D)28.7 m/s E)31.5 m/s

Question

Quizplus · Accepted Answer

The correct answer is A because the car will begin to slide when the centripetal force provided by friction is less than the centripetal force required to keep the car moving in a circle. The centripetal force provided by friction is given by f_s = u_s * n, where u_s is the coefficient of static friction and n is the normal force. The normal force is equal to the weight of the car, which is given by n = m * g, where m is the mass of the car and g is the acceleration due to gravity. The centripetal force required to keep the car moving in a circle is given by f_c = m * v^2 / r, where v is the speed of the car and r is the radius of the curve. When the centripetal force provided by friction is less than the centripetal force required to keep the car moving in a circle, the car will begin to slide.

A Race Car Enters a Flat 200-M Radius Curve at a Speed