The following four forces act on a 4.00 kg object:
F₁ = 300 N east
F₂ = 700 N north
F₃ = 500 N west
F₄ = 600 N south
What is the acceleration of the object?

Question

The following four forces act on a 4.00 kg object: F₁ = 300 N east F₂ = 700 N north F₃ = 500 N west F₄ = 600 N south What is the acceleration of the object?

Quizplus · Accepted Answer

To find the acceleration of the object, we first need to find the net force acting on it:
Net force in the x-direction = 300 N west - 500 N east = -200 N east
Net force in the y-direction = 700 N north - 600 N south = 100 N north
Using the formula F=ma, we can find the acceleration:
-200 N east + 100 N north = ma
Magnitude of net force, Fnet = sqrt((-200 N)^2 + (100 N)^2) = 224 N
Direction of net force, θ = atan(100 N / 200 N) = 26.6° north of west
Using the formula a=F/m, we can find the acceleration:
a = 224 N / 4.00 kg = 56.0 m/s^2
Therefore, the acceleration of the object is 56.0 m/s^2 in a direction 26.6° north of west. The answer is choice D.

The Following Four Forces Act on a 4