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FIGURE 4-11 -The Free-Body Diagram of an 8.00 Kg Object Is Shown

Question 73

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FIGURE 4-11 FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg)
-The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object?


A) (6.0 N sin 28° - 5.0 N sin 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) + (6.0 N cos 28° + 5.0 N cos 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) = (8.00 kg) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg)
B) (6.0 N cos 28° + 5.0 N cos 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) + (6.0 N sin 28° + 5.0 N sin 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) = (8.00 kg) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg)
C) (6.0 N cos 28° - 5.0 N sin 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) + (6.0 N sin 28° + 5.0 N cos 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) = (8.00 kg) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg)
D) (6.0 N cos 28° - 5.0 N cos 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) + (6.0 N sin 28° + 5.0 N sin 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) = (8.00 kg) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg)
E) (6.0 N cos 28° + 5.0 N sin 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) + (6.0 N sin 28° - 5.0 N cos 22°) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg) = (8.00 kg) FIGURE 4-11 -The free-body diagram of an 8.00 kg object is shown in Fig. 4-11. What is Newton's Second Law for this object? A) (6.0 N sin 28° - 5.0 N sin 22°) + (6.0 N cos 28° + 5.0 N cos 22°) = (8.00 kg) B) (6.0 N cos 28° + 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) C) (6.0 N cos 28° - 5.0 N sin 22°) + (6.0 N sin 28° + 5.0 N cos 22°) = (8.00 kg) D) (6.0 N cos 28° - 5.0 N cos 22°) + (6.0 N sin 28° + 5.0 N sin 22°) = (8.00 kg) E) (6.0 N cos 28° + 5.0 N sin 22°) + (6.0 N sin 28° - 5.0 N cos 22°) = (8.00 kg)

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