A 4.00-kg block slides down a frictionless inclined plane with an acceleration 3.00 m/s². What is the angle of the incline above horizontal? A) 35.3° B) 45.2° C) 17.8° D) 23.6° E) 53.7°

Question

Quizplus · Accepted Answer

First, we can use the formula for the acceleration of an object sliding down an inclined plane with no friction:

a = g sin(θ)

where a is the acceleration, g is the acceleration due to gravity (9.81 m/s^2), and θ is the angle of the incline above horizontal.

Substituting the values given in the problem:

3.00 m/s^2 = 9.81 m/s^2 sin(θ)

Solving for θ:

θ = sin^-1(3.00 m/s^2 / 9.81 m/s^2) = 17.8°

Therefore, the answer is C.

A 400-Kg Block Slides Down a Frictionless Inclined Plane with an an Acceleration