A car is moving with a velocity (3.0 m/s)^x + (1.0 m/s)^y and 2.5 seconds later its velocity is (6.0 m/s)^x - (3.0 m/s)^y. What is the magnitude of the average acceleration of the car? A)0.82 m/s² B)1.6 m/s² C)2.0 m/s² D)4.5 m/s² E)6.2 m/s²

Question

Quizplus · Accepted Answer

The average acceleration is calculated by finding the change in velocity divided by the time interval. The change in velocity is (6.0 - 3.0) m/s in the x-direction and (-3.0 - 1.0) m/s in the y-direction, resulting in a change of (3.0 m/s)^x and (-4.0 m/s)^y. The magnitude of this change is √((3.0)^2 + (-4.0)^2) = 5.0 m/s. Dividing by the time interval of 2.5 seconds gives an average acceleration magnitude of 2.0 m/s².

A Car Is Moving with a Velocity (3