A projectile is launched from ground level at an angle of 50.0° above horizontal with a speed of 30.0 m/s. If the projectile is moving over level ground, how long is it in the air before it again contacts the ground?
A)8.12 s
B)2.35 s
C)4.69 s
D)6.44 s
E)11.3 s

Question

Quizplus · Accepted Answer

The time of flight for a projectile launched at an angle θ with initial speed v is given by the formula T = (2 * v * sin(θ)) / g, where g is the acceleration due to gravity (approximately 9.81 m/s²). Substituting the given values, T = (2 * 30.0 m/s * sin(50°)) / 9.81 m/s² ≈ 4.69 s.

A Projectile Is Launched from Ground Level at an Angle